302 Roulette Systems (302 Sistemas de Ruleta)

3 Columns Method

This is a method that picked up during mi travels through Europe. I have played it myself from time to time and found that it will work succesfully, it does, however, require a large bankroll if any great amount of money is to be made. And remember this: you can lose.
I have found, however, that if played in moderation, your chances ofleaving the tables a winner are in your favor.

To start, let us imagine thet the ball has landed on the color red. Now looking at either the American or European version of the roulette wheel, you will notice that the column starting at (1) and running down to number 34 contains 6 reds as well as 6 blacks. Moving on to the middle column, starting at number 2 and runnig down to number 35, we now have 4 reds and 8 blacks. The third column, from 3 to number 36, has 8 reds and only 4 blacks.

You will also note that althought the numbers are in the correct order, 1 2 3 4 5 6 7 to 36, the colors only seem to run in a red, black, red, black, red, black sequence. Number 11, which should be red if following a true pattern, is black. Number 19, further down, is red, not black, 29 is black, not the expected red.

Now that we have an idea of the columns, let us go a step further.

By watching the wheel spun for a free turn, we establish that the ball has landed in red. Count the number of reds in the first column (1 to 34). There are 6. In the second column there are only 4. In the third column there are 8. If we are to cover as many reds are possible –by playing two columns at the same time- we would pick the first and third, which gives us a total of 14 reds (if we were to play the first and second, we would only be covering 10 reds). You can see the advantage of playing the first ant third columns – we have gained 4 reds over the first and second, and 2 reds over the second and third.

We have now established a type of pattem. If the ball has landed in red on our free spin, we would then place our bets in the first and third columns, giving us the grather number of reds covered for the next spin.

Should the ball have landed in the black, we would play the first and seconds columns, incorporating the greatest number of blacks.

Remember, we are not only covering the mayority of reds or blacks. We are also covering the 14 blacks that appear in columns one and three, and the 14 reds in columns one and two.

We are now covering a total of 24 numbers, giving us 14 reds with 4 reds against us; and 10 blacks, with 8 blacks against us. Counting the single 0 and double 00 out of the 38 numbers on the layout, we are covering 24 numbers. This leaves 14 numbers against us.

No matter what two columns you play, you can only cover 24 numbers. But key is not to cover the gratest amount of numbers, but the greatest number of colors.

The advantage to playing this method is that the payoff is 2 to 1.

Let us try a sample game and see what happens. Below is a record of 20 games played.

Having had our free spin whit the color red winning, our bet would be $50 on the first and third columns (this would give us 14 reds and 10 blacks). Number 19 reds wins, which is in the first column.

So we have won in the first column and are paid off $100, we lost $50 in the third column. We are a $50 winner. Because 19 red won, we will now continue to play the first and third columns, covering again the greatest number of reds along with 10 blacks.

Number 27 red wins this time. Because 27 is in the third column, we have another win and another profit of $50. We now continue to play the first and third columns. At the end of the roll we see that 6black hits. Six is in the third column, giving us another win $100 in column three. However, we've los $50 on column one, measuring a gain of $50.

Because black won, we will now switch from the first and third columns to the first and second columns, thereby covering the majority of blacks (along with 10 reds). We see that number 11 blacks wins. Because we have been playing the first and second columns, and because 11 is in the second column, we win another $100 and lose $50, a profit of $50 again.

Now, because 11 black has hit, we stay with the first and second columns. Number 9 hits. We lose our money - $50 in the first column and $50 in the second – a total of $100.

Because red has hit, we now move our bets, placing $50 on the first column and $50 on the third column, once again covering the majority of reds. Number 4 wins, making us $100 from the first column and losing us $50 in the third. Still sticking with black by playing the first and second columns, we see that number 24 black hits: 24 is in the third column, so we lose $100.

Because the color still black we stay with the first and second columns, giving us once again the advantage of the blacks. Number 10 in the black hits, giving us a win of $100 on the first column and a loss of $50 in the second.

Because it was black, we will now stay with the first and second columns. Number 12 red hits; 12 is in the third column not the ones we were playing – so we lose $100. Because 12 red has hit, we now move to the first and third columns, therefore giing us the advantage of reds. Number 6 in the black wins -$100 gained and $50 lost.

Because 6 black has hit, we now play the first and second columns, covering the most blacks. Number 34 red hits; 34 is in the first column, so our profit is $100 and our loss is $50. Because it was red, we will now play the first and third columns. Now, number 20 black hits – a loss of $100.

We now switch to the first and second columns. Number 5 red wins – we're up $50. Because it was red, we will go now to the first and third columns. Number 9 red wins – another $50 profit.

Because it was red, we stay with red, still covering the first and third columns, and number 27 red hits – another profit of $50. Because it was red, we stay with the first and third columns and we notice the next number up is 10 black, in the first column – another $50. Because it was black that won, we now play the first and second columns. Number 2 black hits – an aditional $50 profit.

So we stay with the first and second columns, but 9 red hits – a loss on both the first and second columns of $50 apiece. Because red has hit, we now switch from the first and second to the first and third columns. Number 14 red hits. We are not covering the middle column where number 14 is located, so we lose another $100. Because it was 14 red, we stay with the first and third columns and find that number 7 red hits – a profit again of $50.

Out of the 20 spins on the wheel and by betting $50 each time, whether we won or we lost, on either one and three columns or one and two columns, we have gained a profit, after 20 rolls, of $100. Now we were $200 up at the end of the fourth roll, after beginning, so the idea of the system, pretty well, is that you set out to make a certain amount of dollars. Normally, if you make $200 or $300, you would quit. The amount of money you are betting determines how fast you will make this. Some people play the table limit. If the table limit is $500, they play until they are exactly $500 ahead. The could do this on the first spin of the wheel, or they could invest $5000 – and still there really no guarantee that they will make their $500 unless they are a financial position to carry on with an unlimited amount of money until they made their win of $500. Remember, always bet the same amount on each column you are playing.

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